A 10.0 mL Syringe: Calculating Pressure Inside
Calculating Pressure Inside a 10.0 mL Syringe
A 10.0 mL syringe contains 0.10 g of nitrogen gas at 0.0 degrees Celsius. What is the pressure inside the syringe?
Since the sample inside the syringe is a gas, we assume that it is an ideal gas, which means we can use the ideal gas law equation PV = nRT. Let's calculate the pressure inside the syringe:
n = m / M
Where:
n = number of moles
m = mass of the gas (0.10 g)
M = molar mass of nitrogen gas (28 g/mol)
Plugging in the values, we get:
n = 0.10 / 28 = 0.0036 mol
P = nRT / V
Where:
P = pressure
R = ideal gas constant (0.08206 atm·L/mol·K)
T = temperature in Kelvin (0 degrees Celsius = 273.15 K)
V = volume of the syringe (10.0 mL = 0.010 L)
Substitute the values into the equation:
P = 0.0036(0.08206)(273.15) / 0.010
P = 8 atm
What is the pressure inside the 10.0 mL syringe that contains 0.10 g of nitrogen gas at 0.0 degrees Celsius?
The pressure inside the syringe is 8.0 atm.