A Solution Dilution Problem: What Was the Original Concentration?

What was the original concentration of a solution that was diluted from 0.93 L to 0.917 M by adding 1.065 L of solvent?

The original concentration of the solution can be determined using the formula for molarity, which relates the initial molarity and volume to the final molarity and volume:

Molarity and Dilution Calculation

The formula for molarity is defined as the number of moles of solute per liter of solution and can be represented as M = mol/L. In this case, the molarity of the original solution, M₁, can be calculated using the formula:

M₁ = M₂V₂ / V₁

Given that the final molarity (M₂) is 0.917 M, the final volume (V₂) is 1.065 L, and the initial volume (V₁) is 0.93 L, we can substitute these values into the formula:

M₁ = 0.917 × 1.065 / 0.93 = 1.050 M

Therefore, the original concentration of the solution was 1.050 M.

← What is iron pyrite and how is it used as an ore for sulphur Boyle s law calculating the new pressure of a compressed gas →