Chemical Reaction: Calcium Carbide and Water
How many grams of acetylene (C2H2) are produced when 10.0 g of CaC2 reacts with excess water?
10.0 g of CaC2 will produce 4.07 g of acetylene (C2H2) when reacted with excess water.
Explanation:
CaC2 + 2H2O → Ca(OH)2 + C2H2
From the balanced equation, we can see that for every 1 mole of CaC2, 1 mole of C2H2 is produced. To calculate the number of grams of C2H2 produced, we need to convert the given mass of CaC2 to moles using its molar mass, and then use the mole ratio to find the mass of C2H2:
Molar mass of CaC2 = 40.08 g/mol + 12.01 g/mol x 2 = 64.10 g/mol
Number of moles of CaC2 = 10.0 g / 64.10 g/mol = 0.156 moles
Number of moles of C2H2 = 0.156 moles
Mass of C2H2 = number of moles x molar mass = 0.156 moles x 26.04 g/mol = 4.07 g
Conclusion: When 10.0 g of CaC2 reacts with excess water, 4.07 g of acetylene (C2H2) is produced.