Chemical Reaction: Calculate the Theoretical Volume of Hydrogen Gas Produced

What is the theoretical volume of hydrogen gas produced in the given chemical reaction?

At 22°C and 0.998 atm, what is the theoretical volume (in ml) of hydrogen gas produced when 1.12g of pure zinc metal reacts with 8.00ml of 1M hydrochloric acid?


The reaction of zinc with hydrochloric acid produces hydrogen gas. Given the quantities and conditions stated in the question, it can be calculated that the theoretical volume of the hydrogen gas produced is approximately 421 milliliters.

Explanation: This question pertains to the reaction of zinc with hydrochloric acid, which produces hydrogen gas. From the known chemical reaction, we can see that 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of hydrogen gas. Given that the molar mass of Zn is approximately 65.38 g/mol, 1.12g of Zn translates to roughly 0.0171 moles. Consequently, the theoretical volume of hydrogen gas produced can be calculated using the formula V=nRT/P. Here, n is the number of moles, R is the gas constant (0.0821 L·atm/K·mol), T is the temperature in kelvins (which is 22+273.15 = 295.15 K), and P is the pressure in atm (0.998 atm). Performing these calculations gives a volume of approximately 0.421 liters, which is equivalent to 421 ml. Assuming all of the zinc reacted, this is the theoretical volume of hydrogen gas produced.

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