Chemical Reaction: Calculating Dimethylglyoxime Solution Volume
How to calculate the volume of dimethylglyoxime solution needed for Reaction 7-2?
Given data: 0.998 4 g of steel with 2.07 wt% Ni and 2.15 wt% dimethylglyoxime solution with a density of 0.790 g/mL.
Answer:
The volume of solution required is 7.195 mL.
First, calculate the mass of Ni in the steel sample:
Mass of Ni = 0.9984 g x 2.07% = 0.0206 g
Next, determine the moles of Ni:
Moles of Ni = 0.0206 g / 58.7 g/mol = 0.0003509 mol
Calculate the moles of dimethylglyoxime needed:
Since 1 mole of Ni requires 2 moles of dimethylglyoxime, the moles needed for a 50% excess are 0.0010527 mol.
Find the mass of dimethylglyoxime:
Mass of dimethylglyoxime = 0.0010527 mol x 116.12 g/mol = 0.1222 g
Determine the weight of the solution:
0.1222 g of dimethylglyoxime corresponds to 5.684 g of the solution
Calculate the volume of the solution:
Density = 0.790 g/mL = 5.684 g / Volume
Therefore, Volume of solution = 7.195 mL
Final answer: Approximately 7.195 mL of a 2.15 wt% dimethylglyoxime solution should be used to provide a 50% excess for Reaction 7-2 with the given steel sample containing 2.07 wt% Ni.