Chemical Reaction: Finding the Concentration of NaOH Used
What is the concentration of NaOH that is used?
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
c₁=2.00 mol/L
v₁=0.25 L
v₂=2.00 L
c₂-?
n(NaOH)=c₂v₂
n(H₂SO₄)=c₁v₁
n(NaOH)=2n(H₂SO₄)
c₂v₂=2c₁v₁
c₂=2c₁v₁/v₂
c₂=2*2.00*0.25/2.00=0.5 mol/L
0.5 M NaOH
Answer:
0.5 M is the concentration of NaOH used.
Explanation:
Considering:
Molarity= Moles of solute / Volume of the solution
Or,
Moles = Molarity x Volume of the solution
Given :
For H₂SO₄ :
Molarity = 2.00 M
Volume = 0.25 L
Thus, moles of H₂SO₄ :
Moles = 2.00 x 0.25 moles
Moles of H₂SO₄ = 0.5 moles
According to the given reaction:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
1 mole of H₂SO₄ reacts with 2 moles of NaOH
0.5 mole of H₂SO₄ reacts with 2 x 0.5 moles of NaOH
Moles of NaOH = 1.0 moles
Given that volume of NaOH reacted = 2.00 L
So,
Molarity= Moles of solute / Volume of the solution
Molarity= 1.0 / 2.00 M = 0.5 M
0.5 M is the concentration of NaOH used.