Chemical Reactions and Limiting Reagents: A Creative Approach

What is the limiting reagent and the volume of CO2 formed when 11 L CS2 reacts with 18 L O2 to produce CO2 gas and SO2 gas at STP? The answer is option b) O₂; 6.0 L C0₂

When dealing with chemical reactions, determining the limiting reagent is crucial in understanding the extent of the reaction. In this particular case, we are looking at the reaction between CS2 and O2 to produce CO2 and SO2 at STP conditions.

The balanced reaction is as follows:

CS₂ (g) + 3 O₂(g) → CO₂(g) + 2 SO₂(g)

STP conditions refer to standard temperature and pressure, where pressure is 1 atmosphere and temperature is 0°C. Under these conditions, 1 mole of any gas occupies approximately 22.4 liters.

To determine the limiting reagent, we need to calculate the moles of CS2 and O2 based on the given volumes. By using the rule of three and stoichiometry, we find that O2 is the limiting reagent in this reaction.

Once we establish the limiting reagent, we can then calculate the moles of CO2 formed using stoichiometry and the rule of three. The volume of CO2 formed can then be determined based on the number of moles formed and the STP conditions.

Therefore, the correct answer is option b) O₂; with 6.0 L of CO₂ formed in this reaction.

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