Chemistry Problem: Determining Number of Molecules in Tin (IV) Nitrate

How many molecules (or atoms) of tin (IV) nitrate would contain 6.17 moles of oxygen atoms?

Given parameters: Number of moles of oxygen atoms = 6.17 moles

Unknown: Number of molecule of tin(IV) nitrate = ?

Answer: 3.01 x 10²³ molecules

In this chemistry problem, we are tasked with determining the number of molecules of tin (IV) nitrate that would contain 6.17 moles of oxygen atoms. This type of problem involves stoichiometry, where we use the mole ratios from chemical formulas to calculate the desired quantity.

Given that there are 6.17 moles of oxygen atoms, we need to find out how many molecules of tin (IV) nitrate are required to contain this amount of oxygen atoms.

To solve this problem, we first write the formula of tin (IV) nitrate, which is N₄O₁₂Sn. From this formula, we can determine the mole ratio between oxygen atoms and tin (IV) nitrate.

Since 1 mole of N₄O₁₂Sn contains 12 moles of oxygen atoms, we can calculate that 0.5 mole of N₄O₁₂Sn will contain 6.17 moles of oxygen atoms (6.17/12 = 0.5).

Next, we use Avogadro's number to convert moles to molecules. We know that 1 mole of any substance contains 6.02 x 10²³ molecules. Therefore, 0.5 mole of N₄O₁₂Sn will contain 0.5 x 6.02 x 10²³ = 3.01 x 10²³ molecules.

So, the answer to the question is that 3.01 x 10²³ molecules of tin (IV) nitrate would contain 6.17 moles of oxygen atoms.