Graham's Law of Diffusion: Rate of Nitrogen Dioxide Effusion
What is the rate at which nitrogen dioxide will effuse?
The rate at which the nitrogen dioxide, NO₂ will effuse is 64 mL/s
Explanation:
According to Graham's law of diffusion, the rate of diffusion of a gas is inversely proportional to the square root of the molar mass. The formula for this law is R₁/R₂ = √(M₂/M₁).
Given data:
- Rate of N₂ (R₁) = 82 mL/s
- Molar mass of N₂ (M₁) = 28 g/mol
- Molar mass of NO₂ (M₂) = 46 g/mol
To determine the rate at which nitrogen dioxide, NO₂, will effuse, we can use the Graham's law of diffusion formula.
Applying the equation:
R₁/R₂ = √(M₂/M₁)
82 / R₂ = √(46 / 28)
Cross multiply:
82 = R₂√(46 / 28)
Divide both sides by √(46 / 28)
R₂ = 82 /√(46 / 28)
R₂ = 64 mL/s
Therefore, nitrogen dioxide, NO₂, will effuse at 64 mL/s.