How many moles of oxygen are in 1.6 mol of Ca(NO3)2?

Calculating Moles of Oxygen in Ca(NO3)2

In chemistry, the calculation of moles is a fundamental concept that allows us to determine the amount of a substance in a given sample. When dealing with compounds like Ca(NO3)2, it is essential to understand how to calculate the number of moles of specific elements within the compound.

Let's dive into a specific example: determining the number of moles of oxygen in 1.6 mol of Ca(NO3)2. This question requires us to analyze the chemical composition of Ca(NO3)2 and apply the principles of molar ratios to find the answer.

Question:

How many moles of oxygen are in 1.6 mol of Ca(NO3)2?

a. 1.6 mol

b. 3.2 mol

c. 4.8 mol

d. 9.6 mol

Final answer:

There are 9.6 mol of oxygen in 1.6 mol of Ca(NO3)2.

Explanation:

To determine the number of moles of oxygen in 1.6 mol of Ca(NO3)2, we need to examine the chemical formula of Ca(NO3)2. In this formula, there are two NO3 groups, each consisting of one nitrogen atom (N) and three oxygen atoms (O). Therefore, each Ca(NO3)2 molecule contains six oxygen atoms in total.

Given that we have 1.6 mol of Ca(NO3)2, we can multiply this value by the number of oxygen atoms per mole to find the total number of moles of oxygen. 1.6 mol * 6 mol of oxygen/mol of Ca(NO3)2 = 9.6 mol of oxygen.

Therefore, there are 9.6 mol of oxygen in 1.6 mol of Ca(NO3)2.