Specific Heat Capacity of Ice Calculation
What is the specific heat capacity of ice in units of J/g⋅°C?
How can we calculate the specific heat capacity of ice?
Specific Heat Capacity of Ice Calculation:
The specific heat capacity of ice can be calculated using the formula:
q = m * c * ΔT
To calculate the specific heat capacity of ice, we first need to determine the amount of heat absorbed, the mass of ice, and the change in temperature.
Given that 6.80 g of ice absorbs 0.149 kJ of heat and the temperature changes from 0.0 °C to 10.5 °C:
First, calculate the mass of the ice:
density = mass / volume
mass = density * volume = 0.917 g/cm³ * (6.80 g / 0.917 g/cm³) = 50 g
Next, calculate the change in temperature:
ΔT = 10.5 °C - 0.0 °C = 10.5 °C
Then, plug in the values for q, m, and ΔT to solve for c:
c = q / (m * ΔT) = 0.149 kJ / (50 g * 10.5 °C) = 0.283 J/g⋅°C
Therefore, the specific heat capacity of ice is 0.283 J/g⋅°C.