Determining Synchronous Speed of an AC Motor

What is the synchronous speed of a 2-pole, 60-hertz AC motor?

Answer:

The synchronous speed of a 2-pole, 60-hertz AC motor is 3600 RPM.

The synchronous speed of an AC motor is an important parameter to understand in the field of electrical engineering. In this case, for a 2-pole, 60-hertz AC motor, the synchronous speed is calculated as 3600 RPM.

Explanation:

To determine the synchronous speed of a 2-pole, 60-hertz AC motor, we use the formula:

Synchronous speed (in RPM) = (120 * frequency) / number of poles

Given that the motor has 2 poles and operates at a frequency of 60 hertz, we can substitute these values into the formula:

Synchronous speed (in RPM) = (120 * 60) / 2 = 3600 RPM

Therefore, the synchronous speed of the 2-pole, 60-hertz AC motor is 3600 RPM. This value represents the rotational speed at which the magnetic field of the stator rotates in sync with the rotor.

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