A bullet leaves the barrel at 853 m/s
Calculating the acceleration of a bullet
A bullet leaves the barrel of a Barrett M82 at approximately 853 m/s. If the bullet slows to a velocity of 520 m/s at a range of 1500 m, what is the acceleration of the bullet?
To find the acceleration of the bullet, we can use the formula:
Acceleration = change in velocity / change in time
Given data:
- Initial velocity (u) = 853 m/s
- Final velocity (v) = 520 m/s
- Time taken (t) = 3.0 seconds
First, let's calculate the change in velocity:
Change in velocity = Final velocity - Initial velocity
Change in velocity = 520 m/s - 853 m/s = -333 m/s
Next, we can plug in the values into the formula to find the acceleration:
Acceleration = (-333 m/s) / (3.0 seconds)
Acceleration ≈ -111 m/s²
Therefore, the acceleration of the bullet is approximately -111 m/s². The negative sign indicates that the bullet is decelerating.
What is the acceleration of the bullet?
The acceleration of the bullet is approximately -111 m/s².