A Soccer Ball in Projectile Motion

The Time Spent by a Soccer Ball in the Air

A soccer ball is kicked with an initial resultant velocity of 10m/s and an initial horizontal velocity of 6.4m/s. How many seconds was the ball in the air?

Question:

How many seconds was the soccer ball in the air after being kicked?

Final Answer:

The soccer ball, kicked with an initial resultant velocity of 10m/s and an initial horizontal velocity of 6.4m/s, spends approximately 1.55 seconds in the air.

This question falls under the subject of Physics, specifically projectile motion. By calculating the time the ball spent in the air based on its initial velocities, we found that it takes around 1.55 seconds for the soccer ball to travel through the air.

To arrive at this answer, we first calculated the vertical velocity component using Pythagoras theorem. By subtracting the square of the horizontal velocity from the square of the resultant velocity, we determined that the vertical velocity component is 7.6m/s. We then applied the equation for the time of flight t = 2 * Voy / g, where g represents the acceleration due to gravity (approximately 9.8m/s^2). Upon substituting the values into the equation, we obtained t = 2 * 7.6m/s / 9.8m/s^2 = 1.55 seconds, indicating that the soccer ball remains airborne for approximately 1.55 seconds.