Calculating Resistance of a Light Bulb
What is the resistance of a 100-watt light bulb operated by a 110-volt DC source?
Can you calculate the resistance of the light bulb based on the given power and voltage?
Calculating the Resistance of the Light Bulb
To calculate the resistance of the light bulb, we can use the power formula along with Ohm's Law.
The power formula is:
P = V² / R
Where P is power, V is voltage, and R is resistance.
Given the power of the light bulb is 100 watts and the voltage is 110 volts, we can substitute these values into the formula:
100 = 110² / R
Solving for R, we get:
R = 121 Ω
Explanation of Resistance Calculation
When a 100-watt light bulb is connected to a 110-volt DC source, we can determine the resistance of the bulb by using the power formula. The power dissipated in the bulb is given by the formula P = V² / R, where P is the power, V is the voltage, and R is the resistance.
Substituting the values of power and voltage into the formula, we can solve for the resistance. In this case, the resistance of the light bulb is 121 Ω.
Understanding how to calculate resistance based on power and voltage is essential in electrical engineering and circuit analysis. It allows us to determine the behavior of components in a circuit and ensure proper functioning of electronic devices.
Therefore, the resistance of the 100-watt light bulb operated by a 110-volt DC source is 121 Ω.