Gas Volume Calculation with Charles' Law

What is the volume of gas if you move it to a cooler region with a temperature of 3.00° C?

Given initial gas temperature is 26.0° C and volume is 1.75 L.

Answer

The volume of the gas if you move the assembly to a cooler region with a temperature of 3.00° C is 1.62 L.

Charles' Law describes the relationship between the volume of a gas and its temperature at constant pressure. According to Charles' Law, the volume of a gas is directly proportional to its temperature in Kelvin.

In this particular problem, we are given an initial gas temperature of 26.0° C and a volume of 1.75 L. The final temperature is 3.00° C.

Charles' Law formula is expressed as [V₁/T₁ = V₂/T₂], where V₁ is the initial volume, T₁ is the initial temperature, V₂ is the final volume, and T₂ is the final temperature.

Substitute the given values into the formula to calculate the final volume of the gas when moved to a cooler region with a temperature of 3.00° C:

V₂ = V₁ * (T₂ / T₁)

V₂ = 1.75 L * (276 K / 299 K)

V₂ = 1.62 L

Therefore, the volume of the gas when moved to a cooler region with a temperature of 3.00° C is 1.62 L.

Charles' Law is a fundamental principle in gas laws that helps explain the behavior of gases under varying conditions. By understanding this law, scientists and engineers can make accurate predictions and calculations related to gas volume and temperature changes.