# High-Speed Train Acceleration Calculation

## What is the speed of a high-speed train after 5 minutes of constant acceleration?

Given data: Initial velocity (u) = 0 m/s Acceleration (a) = 0.9 m/s^2 Time (t) = 5 minutes or 300 seconds Speed (v) = ?

## Answer

The speed that the high-speed train reaches after 5 minutes is 972 km/h.

To calculate the final speed of the high-speed train, we can use the equation of motion: v = u + at, where: - v is the final velocity, - u is the initial velocity, - a is the acceleration, and - t is the time. Plugging in the values: - u = 0 m/s, - a = 0.9 m/s^2, and - t = 300 seconds, we get: v = 0 + (0.9 * 300) v = 270 m/s To convert the final speed to km/h, we use the conversion factor: 1 m/s = 3.6 km/h Therefore, 270 m/s * 3.6 = 972 km/h. So, the high-speed train's speed after 5 minutes of constant acceleration is 972 km/h.