How Much Work is Required to Stop a Rolling Hoop?
What is the amount of work that must be done on a 150 kg hoop rolling along a horizontal floor to stop it?
When a 150 kg hoop rolls along a horizontal floor with a center of mass speed of 0.220 m/s, the work done on the hoop to stop it is -3.66 J. The work done on the hoop is equal to the change in kinetic energy of the hoop, which can be calculated using the formula: Work done = ∆KE = 1/2 mv². Given the initial velocity (v) of the hoop, we can determine the kinetic energy of the hoop while it's in motion. Using the formula for kinetic energy: Kinetic energy = 1/2mv², where m = mass of the hoop and v = velocity of the hoop, substitute the values into the equation: Kinetic energy = 1/2 × 150 kg × (0.220 m/s)² = 3.66 J As the hoop comes to a stop, the final velocity of the hoop is 0, and the work done on the hoop can be calculated as: Work done = ∆KE = KE final - KE initial. Therefore, the work done on the hoop to stop it is -3.66 J. The answer to the question of how much work is required to stop a rolling hoop is -3.66 J.Calculating Work Done on the Hoop