Impulse Calculation in Baseball

What is the magnitude and direction of the impulse delivered by the bat to the ball?

A 140 g baseball is moving horizontally to the right at 35 m/s when it is hit by the bat. The ball flies off to the left at 55 m/s, at an angle of 25° above the horizontal.

Answer:

The magnitude of the impulse delivered by the bat to the ball is 12.32 kg*m/s.

When analyzing the impulse in this scenario, we first converted the mass of the baseball from 140 g to 0.140 kg. The initial velocity of the baseball was 35 m/s to the right, and after being hit by the bat, it flew off to the left at 55 m/s at an angle of 25° above the horizontal.

We broke down the velocity components into horizontal and vertical components to calculate the impulse accurately. The impulse equation involves finding the difference in momentum, which in this case is the mass of the baseball multiplied by the change in velocity.

By calculating the difference in velocity components and substituting them into the impulse equation, we found that the magnitude of the impulse delivered by the bat to the ball is 12.32 kg*m/s.