Interesting Fact about Projectile Motion

What is the maximum height reached by a ball in projectile motion? The maximum height reached by a ball in projectile motion, considering only the vertical motion and ignoring friction and wind resistance, is around 1.225 meters.

Projectile motion is a fascinating concept that involves objects being launched into the air and moving in a curved path due to the force of gravity. One key aspect of projectile motion is determining the maximum height reached by the object during its trajectory.

When calculating the maximum height reached by a ball in projectile motion, we consider only the vertical component of its motion. This means we focus on the upward and downward movement of the object, excluding any horizontal movements or external forces like air resistance.

To find the maximum height, we can use the formula Hmax = (Voy^2) / (2g), where Voy is the initial vertical velocity of the object and g is the acceleration due to gravity (9.8 m/s²).

For example, if a ball is kicked with an initial vertical velocity of 4.9 m/s and stays in the air for a total time of 1.0 second, the maximum height reached by the ball would be calculated as follows:

Hmax = (4.9 m/s)^2 / (2 * 9.8 m/s²)

Hmax = 24.01 / 19.6

Hmax ≈ 1.225 meters

Therefore, the maximum height reached by the ball in this scenario would be approximately 1.225 meters above the ground at its peak. This calculation provides insight into the vertical motion of the object in projectile motion, helping us understand its trajectory and peak altitude.

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