Projectile Motion for Stunt Driver: Maximum Speed and Minimum Speed Calculation

a) What is the maximum speed the stunt driver must drive off the horizontal ramp to clear 8 cars parked side by side below a horizontal ramp?

Choices: 1. 11 m/s 2. 14 m/s 3. 17 m/s 4. 20 m/s

b) What is the new minimum speed required if the ramp is now tilted upward at a 10-degree angle above the horizontal?

Choices: 1. 16 m/s 2. 18 m/s 3. 20 m/s 4. 22 m/s

Maximum speed calculation for clearing 8 cars:

Minimum speed calculation with ramp tilted at 10-degree angle above horizontal:

Maximum Speed Calculation:

When calculating the maximum speed the stunt driver must drive off the horizontal ramp to clear 8 cars parked side by side, we must consider the vertical height of the ramp, which is 1.5m and the horizontal distance of 20m that needs to be cleared. To find the maximum speed, we can use the principles of projectile motion.

First, we calculate the initial vertical velocity component needed to clear the 1.5m height using the equation v = sqrt(2 * g * h). Then, we determine the time of flight using the equation t = d / (v * cos(theta)), where theta is the launch angle. Finally, we can calculate the maximum speed using the equation v_max = d / (t * cos(theta)).

Minimum Speed Calculation with Tilted Ramp:

When the ramp is tilted upward at a 10-degree angle above the horizontal, the new minimum speed required can be found using the same equations as in part (a), but with the new launch angle taken into account.

By applying the principles of projectile motion and adjusting for the new launch angle, we can calculate the minimum speed needed for the stunt driver to successfully clear the ramp when tilted at 10 degrees above the horizontal.