Reflection on Induced emf in a Wire Moving Across a Magnetic Field
What is the induced emf in the wire?
A. 0.27 volts
B. 1.5 volts
C. 0.65 volts
D. 27 volts
Answer:
The induced emf in the wire is 0.27 volts.
Induced electromotive force (emf) in a wire moving across a magnetic field is a fascinating concept in physics. In this scenario, the length of the wire is 0.65 meters and it is moving perpendicularly across a magnetic field with a velocity of 15 meters/second. The strength of the magnetic field is 2.8 × 10^-2 newtons/ampere·meter.
The formula to calculate induced emf is E = B * L * v, where E is the induced emf, B is the magnetic field strength, L is the length of the wire, and v is the velocity of the wire.
Plugging in the given values into the formula, we get:
E = (2.8 × 10^-2 N/A·m) * (0.65 m) * (15 m/s)
E = 0.27 volts
Therefore, the induced emf in the wire is 0.27 volts. This phenomenon showcases the intricate relationship between magnetic fields, movement, and electromotive force.