Students Catapult Contest: How High Does the Ball Go?
Students Catapult Contest
Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s.
Calculating the Maximum Height
Question: How high does the ball go?
Answer: The height reached by the ball = 0.459 m
Explanation:
We are given that θ = 30 degrees
Initial speed, u = 6 m/s
We have to find the maximum height reached by the ball.
Maximum height reached by ball: h = (u^2sin^2θ) / (2g)
Where g = 9.8 m/s^2
Substitute the values: h = (6^2sin^230 degrees) / (2 * 9.8)
h = (36 * 1/4) / (2 * 9.8)
h = 0.459 m
Hence, the height reached by the ball = 0.459 m
Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s. How high does the ball go?
The height reached by the ball = 0.459 m Explanation: We are given that θ = 30 degrees. Initial speed, u = 6 m/s. We have to find the maximum height reached by the ball. Maximum height reached by ball: h = (u^2sin^2θ) / (2g). Where g = 9.8 m/s^2. Substitute the values: h = (6^2sin^230 degrees) / (2 * 9.8). h = (36 * 1/4) / (2 * 9.8). h = 0.459 m. Hence, the height reached by the ball = 0.459 m