The Distance Traveled by a Movie Stunt Car off a Cliff
How far does the car travel during its fall?
Ignoring air resistance, how far does the car travel during its fall?
a) 20.2 m
b) 40.4 m
c) 60.6 m
d) 80.8 m
Final answer:
The car travels approximately 30.1 meters during its fall from the 44.1 m-high cliff with a horizontal speed of 10.0 m/s.
To find the distance traveled by the car during its fall, we can use the equation for the horizontal distance traveled by a projectile:
d = vx * t
Where d is the distance, vx is the horizontal velocity, and t is the time of flight.
Since the car is falling vertically, the time of flight can be determined by the equation:
t = sqrt((2 * h) / g)
Where h is the height of the cliff and g is the acceleration due to gravity.
Plugging in the values, we have:
t = sqrt((2 * 44.1) / 9.8) ≈ 3.01 s
Now we can find the horizontal distance:
d = 10.0 * 3.01 ≈ 30.1 m
So, the car travels approximately 30.1 meters during its fall.