Work Done by an Electric Motor in Lifting a Mass

What is the minimum time required for an electric motor to lift a 30 kg mass through a distance of 5m?

Minimum Time Calculation

The minimum time required for the electric motor to lift the 30 kg mass through a distance of 5 m is 1.97 seconds.

When dealing with the lifting of a mass by an electric motor, it is crucial to calculate the minimum time required for the task to be completed. In this scenario, we have a 30 kg mass being lifted through a distance of 5 meters. To determine the minimum time needed, we can utilize the following formula:

Work Done (W) = Force × Distance

Given that force is equal to mass multiplied by acceleration due to gravity (9.8 m/s^2) and power is equal to work divided by time, we can express the equation as follows:

Force = 30 kg × 9.8 m/s^2 = 294 N

Work = Force × Distance = 294 N × 5 m = 1470 J

Power = 1.0 hp × 745.7 W/hp = 745.7 W

By substituting the values into the equation for time (Time = Work / Power), we can find that:

Time = 1470 J / 745.7 W = 1.97 seconds

Therefore, the minimum time required for the electric motor to lift the 30 kg mass through a distance of 5 meters is approximately 1.97 seconds. This calculation showcases the efficiency and capability of the electric motor in performing the lifting task within a specified timeframe.