What was the population of the city in 2012?
a) Exponential Growth Function:
The general form of an exponential growth function is:
P(t) = P₀ x (1 + r)^t
where:
P(t) is the population at time t
P₀ is the initial population (5.74 million in this case)
r is the growth rate per year (3.75% = 0.0375)
t is the time in years
Therefore, the specific exponential growth function for this city is:
P(t) = 5.74 x (1 + 0.0375)^t
This function represents the population at any given year t after 2012.
b) Estimate the Population in 2018:
To estimate the population in 2018, we need to find P(6) since 2018 is 6 years after 2012. Plugging in the values:
P(6) = 5.74 x (1 + 0.0375)^6 ≈ 7.04 million
Therefore, the estimated population of the city in 2018 is approximately 7.04 million.
c) When will the Population Reach 8 Million?
We need to find the value of t for which P(t) = 8. Setting up the equation:
8 = 5.74 x (1 + 0.0375)^t
Solving for t using iterative methods or calculators, we get:
t ≈ 8.39 years
Since we only care about whole years, rounding up to 9 gives us the answer.
Therefore, the population of the city will reach 8 million in the year 2021 (2012 + 9 years).
d) Doubling Time:
The doubling time is the time it takes for the population to double its initial value. We can find it using the formula:
doubling time = ln(2) / ln(1 + r)
where ln is the natural logarithm. Plugging in the values:
doubling time ≈ 18.83 years
Therefore, it takes approximately 18.83 years for the city's population to double at its current growth rate
QUESTION: In 2012, the population of a city was 5.74 million. The exponential growth rate was 3.75% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 8 million? d) Find the doubling time. Exponential Growth Function: P(t) = 5.74 x (1 + 0.0375)^t Estimated population in 2018: 7.04 million Year population reaches 8 million is 2021 Doubling time is 18.83 years