Molar Mass Calculation: How Many Moles of Theoretical Compound L2E3 in 25g?

How many moles of theoretical compound L2E3 would be in 25g of the compound?

The molar mass of theoretical element L is 12.19.

The molar mass of theoretical element E is 8.29.

Round your answer to 2 decimal places. Do not include the unit.

Answer:

0.508 moles of theoretical compound L2E3.

To calculate the number of moles of theoretical compound L2E3 in 25g, we first need to determine the molar mass of the compound. To do this, we add the molar masses of the two elements, which gives us:

Molar mass of L2E3 = (2 x molar mass of L) + (3 x molar mass of E)

Molar mass of L2E3 = (2 x 12.19) + (3 x 8.29)

Molar mass of L2E3 = 24.38 + 24.87

Molar mass of L2E3 = 49.25

Now that we know the molar mass of L2E3, we can use it to calculate the number of moles in 25g:

Number of moles of L2E3 = mass of compound / molar mass of compound

Number of moles of L2E3 = 25 / 49.25

Number of moles of L2E3 = 0.508 moles

Therefore, there are 0.508 moles of theoretical compound L2E3 in 25g of the compound.