Boil Your Chemistry Knowledge with Boiling Points

What can we predict about the boiling point of I2 based on the boiling point of F2?

Which of the following best predicts the boiling point of I2?

  1. Lower than -188°C because permanent dipoles created in fluorine are stronger than temporary dipoles in iodine.
  2. Higher than -188°C because dipole-dipole interactions in iodine are stronger than dispersion forces in fluorine.
  3. Lower than -188°C because fluorine is more polar than iodine because of its higher electronegativity.
  4. Higher than -188°C because dispersion forces are stronger in iodine due to a greater number of electrons.

Final Answer:

The boiling point of I2 is predicted to be higher than -188°C due to stronger dipole-dipole interactions in iodine compared to dispersion forces in fluorine.

Explanation:

The boiling point of I2 is predicted to be higher than -188°C because dipole-dipole interactions in iodine are stronger than dispersion forces in fluorine. Although fluorine is more polar than iodine due to its higher electronegativity, it is the dipole-dipole interactions in iodine that contribute to a higher boiling point. Dispersion forces in iodine are stronger due to a greater number of electrons, which further supports the higher boiling point prediction.

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