Exciting Chemistry Problem Solving!

What is the molar mass of the monoprotic acid?

Calculate the molar mass of the acid that was dissolved in water.

Answer:

The molar mass of the acid is 1067.42 g/mol.

Let's dive into the world of chemistry problem solving with an exciting challenge! In this scenario, we have a 2.567-g sample of a monoprotic acid that was dissolved in water. It took 15.24 mL of a 0.1578 M NaOH solution to neutralize the acid. Our task is to calculate the molar mass of the acid.

In order to find the molar mass of the acid, we can follow these steps. First, we need to determine the number of moles of the monoprotic acid by using the information given about the NaOH solution. We know that one mole of NaOH reacts with one mole of the monoprotic acid in an acid-base reaction.

Given that the solution of NaOH has a concentration of 0.1578 M and it took 15.24 mL to neutralize the acid, we can calculate the number of moles of NaOH. This turns out to be 0.002404872 moles of NaOH.

Since the number of moles of the monoprotic acid is equal to the number of moles of NaOH, we can proceed to calculate the molar mass of the acid. By dividing the mass of the acid (2.567 g) by the number of moles (0.002404872 moles), we arrive at a molar mass of 1067.42 g/mol for the monoprotic acid.

With this problem successfully solved, we have unlocked another piece of the intriguing world of chemistry. Keep pursuing knowledge and unraveling the mysteries of science!