Mass of Propane Vaporization Calculation
How can we calculate the mass of propane that vaporizes as a result of absorbing 100.0 kJ of energy?
Given data:
Energy absorbed: 100.0 kJ
Molar enthalpy of vaporization of propane: 15.7 kJ/mol
Molar mass of propane: 44.1 g/mol
Calculation of Mass of Propane Vaporization
To calculate the mass of propane that would vaporize as a result of absorbing 100.0 kJ of energy, we can use the equation:
q = (ΔHvap) * (n)
To calculate the mass of propane vaporization, we first need to determine the number of moles of propane involved. This can be done by dividing the energy absorbed by the molar enthalpy of vaporization:
n = q / ΔHvap
Substitute the given values:
n = 100.0 kJ / 15.7 kJ/mol
n ≈ 6.369 moles
Finally, we can calculate the mass of propane that vaporizes by multiplying the number of moles with the molar mass of propane:
Mass = n * molar mass
Mass = 6.369 moles * 44.1 g/mol
Mass ≈ 281.1 grams